Find the Normal vector of plane
Calculate the normal unit vector of a face or plane  | To derived the normal unit vector n of a plane/face, we can use any two vectors that lie on the plane. PQ and PS in this example | | | Qx - Px | | | PQ = | | Qy - Py | | | | | Qz - Pz | | | | | Sx - Px | | | PS = | | Sy - Py | | | | | Sz - Pz | | | | | ( PQy × PSz ) - ( PQz × PSy ) | | | The normal vector n = | | ( PQz × PSx ) - ( PQx × PSz ) | | | | | ( PQx × PSy ) - ( PQy × PSx ) | | | | | | ( (Qy - Py) × (Sz - Pz) ) - ( (Qz - Pz) × (Sy - Py) ) | | | The normal vector n = | | ( (Qz - Pz) × (Sx - Px) ) - ( (Qx - Px) × (Sz - Pz) ) | | | | | ( (Qx - Px) × (Sy - Py) ) - ( (Qy - Py) × (Sx - Px) ) | | To calculate the unit vector: First calculate the length of the normal vector l = √( nx2 + ny2 + nz2 ) | | | nx / l | | | The unit vector n = | | ny / l | | | | | nz / l | |
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