How to calculate the angle between two 3D vectors
Calculate the angle between two intersecting unit vectors  | If we wish to find the angle created by 3 points P, Q and S we must derived the unit vectors PQ and RS | | | Qx - Px | | | PQ = | | Qy - Py | | | | | Qz - Pz | | | | | Sx - Px | | | PS = | | Sy - Py | | | | | Sz - Pz | | | | Convert to unit vectors: | PQ length, PQl = √( PQx2 + PQy2 + PQz2 ) | | | PQx / PQl | | | Convert PQ to a unit vector = | | PQy / PQl | | | | | PQz / PQl | | PS length, PSl = √( PSx2 + PSy2 + PSz2 ) | | | PSx / PSl | | | Convert PS to a unit vector = | | PSy / PSl | | | | | PSz / PSl | | | Now we have the 2 unit vectors PQ and PS. The angle α between PQ and PS: α = cos-1(PQ.PS) PQ.PS = ( PQx × PSx ) + ( PQy × PSy ) + ( PQz × PSz ) ∴ α = cos-1( ( PQx × PSx ) + ( PQy × PSy ) + ( PQz × PSz ) )
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